newphpbees
13 Dec 2011, 08:27 PM
Hi...
I have a SELECT Statement to get the Rate and Hours per employee.
$sql = "SELECT em.EMP_NO, em.STATUS, w.RATE, r.Hours
FROM $ADODB_DB.employment AS em
INNER JOIN $ADODB_DB.wage AS w ON em.EMP_ID = w.EMP_ID
LEFT JOIN $PAYROLL.regular_sum_hours AS r ON em.EMP_NO = r.EMP_NO
WHERE em.EMP_ID = '$currentEmpID'";
$RsEarnings = $conn2->Execute($sql);
$Rate = $RsEarnings->fields['RATE'];
$Hours = $RsEarnings->fields['Hours'];
$Hours = substr($Hours, 0, 5);
$Hours = str_replace(':', '.', $Hours);
$Amount = $_POST["Amount"];
$Amount = round(($Hours/8)* $Rate, 2);
and Now I revised it, because I need to add OT_Hours in Hours where the STATUS = 'OffSet'.
here is the revised code:
$sql = "SELECT em.EMP_NO, em.STATUS, w.RATE, r.Hours, o.OT_Hours, o.STATUS
FROM $ADODB_DB.employment AS em
INNER JOIN $ADODB_DB.wage AS w ON em.EMP_ID = w.EMP_ID
LEFT JOIN $PAYROLL.regular_sum_hours AS r ON em.EMP_NO = r.EMP_NO
LEFT JOIN $PAYROLL.ot_data AS o ON r.EMP_NO = o.EMP_NO
WHERE em.EMP_ID = '$currentEmpID' AND o.STATUS = 'OffSet'";
$RsEarnings = $conn2->Execute($sql);
$Rate = $RsEarnings->fields['RATE'];
$Hours = $RsEarnings->fields['Hours'];
$Offset = $RsEarnings->fields['OT_Hours'];
$Hours = substr($Hours, 0, 5);
$Hours = str_replace(':', '.', $Hours);
$Hours = ($Hours + $Offset);
$Amount = $_POST["Amount"];
$Amount = round(($Hours/8)* $Rate, 2);
When I run this revised code I noticed that if the employee has no data in ot_data OT_Hours where STATUS = 'OffSet' the Rate and Hours will not displayed.
I want it even the employee has no data on ot_data the Rate and Hours will still display..
I'm still find the solution for that.
Any help is highly appreciated..
Thank you
I have a SELECT Statement to get the Rate and Hours per employee.
$sql = "SELECT em.EMP_NO, em.STATUS, w.RATE, r.Hours
FROM $ADODB_DB.employment AS em
INNER JOIN $ADODB_DB.wage AS w ON em.EMP_ID = w.EMP_ID
LEFT JOIN $PAYROLL.regular_sum_hours AS r ON em.EMP_NO = r.EMP_NO
WHERE em.EMP_ID = '$currentEmpID'";
$RsEarnings = $conn2->Execute($sql);
$Rate = $RsEarnings->fields['RATE'];
$Hours = $RsEarnings->fields['Hours'];
$Hours = substr($Hours, 0, 5);
$Hours = str_replace(':', '.', $Hours);
$Amount = $_POST["Amount"];
$Amount = round(($Hours/8)* $Rate, 2);
and Now I revised it, because I need to add OT_Hours in Hours where the STATUS = 'OffSet'.
here is the revised code:
$sql = "SELECT em.EMP_NO, em.STATUS, w.RATE, r.Hours, o.OT_Hours, o.STATUS
FROM $ADODB_DB.employment AS em
INNER JOIN $ADODB_DB.wage AS w ON em.EMP_ID = w.EMP_ID
LEFT JOIN $PAYROLL.regular_sum_hours AS r ON em.EMP_NO = r.EMP_NO
LEFT JOIN $PAYROLL.ot_data AS o ON r.EMP_NO = o.EMP_NO
WHERE em.EMP_ID = '$currentEmpID' AND o.STATUS = 'OffSet'";
$RsEarnings = $conn2->Execute($sql);
$Rate = $RsEarnings->fields['RATE'];
$Hours = $RsEarnings->fields['Hours'];
$Offset = $RsEarnings->fields['OT_Hours'];
$Hours = substr($Hours, 0, 5);
$Hours = str_replace(':', '.', $Hours);
$Hours = ($Hours + $Offset);
$Amount = $_POST["Amount"];
$Amount = round(($Hours/8)* $Rate, 2);
When I run this revised code I noticed that if the employee has no data in ot_data OT_Hours where STATUS = 'OffSet' the Rate and Hours will not displayed.
I want it even the employee has no data on ot_data the Rate and Hours will still display..
I'm still find the solution for that.
Any help is highly appreciated..
Thank you